Steve can complete the 100m dash in 10 seconds while Paul can run it in 12 seconds. How does Steve's time compare to Paul's?

A. Steve is 5∕6 as fast as Paul
B. Steve is 5∕6 slower than Paul
C. Steve is 1∕2 as fast as Paul
D. Steve is 1∕2 slower than Paul



a survey in which 400 people were asked to identify the TV channel on which they preferred to watch the evening news.

How many more people preferred WWCN with 41% than WANR with 22%?
A. 164
B. 76
C. 236
D. 68

Respuesta :

So, Steve's time in a ratio to Paul's time:


[tex] \frac{Steven's time}{Pauls's time} = \frac{10}{12} = \frac{5}{6} . [/tex] So Steven's time is [tex] \frac{5}{6} [/tex] times shorter, that is
"Steven is [tex] \frac{5}{6} [/tex] times faster than Paul (I find the phrasing "as fast as" problematic though)

In the second question 41% of 400, which is 4*41=164 people chose WWCN and 22% chose WANR, that is 22%*400=4*22=88.

And the difference is 76 people! ( 164-88=76)B)

Answer:

Q-1 The correct option is A) Steve is 5∕6 as fast as Paul

Q-2 The correct option is 76.

Step-by-step explanation:

Consider the provided information.

Q-1

Steve can complete the 100m dash in 10 seconds while Paul can run it in 12 seconds.

Since, the distance for both are same,

[tex]\frac{\text{Steve's time}}{\text{Paul's time}}=\frac{10}{12}=\frac{5}{6}\\\text{Steve's time}=\frac{5}{6}\text{ of Paul's time}}[/tex]

Hence, Steve's time is 5⁄6 of the time taken by Paul.

Therefore, the correct option is A) Steve is 5∕6 as fast as Paul

Q-2 a survey in which 400 people were asked to identify the TV channel on which they preferred to watch the evening news.

WWCN got  41% and WANR got 22%

For WWCN

41% of 400 is: [tex]\frac{41}{100} \times 400=164[/tex]

That means 164 people preferred WWCN.

For WANR

22% of 400 is: [tex]\frac{22}{100} \times 400=88[/tex]

That means 88 people preferred WANR.

We need to find how many more people preferred WWCN

For this subtract both the values: 164-88=76

Thus, 76 more people preferred WWCN

Hence, the correct option is 76.