1. Acceleration: 242.6 m/s^2
Explanation:
The acceleration of the sled is given by:
[tex]a=\frac{v-u}{t}[/tex]
where
v is the final velocity
u is the initial velocity
t is the time taken for the sled to accelerate from u to v
For the sled in the problem, we have:
u = 0 m/s
v = 444 m/s
t = 1.83 s
Therefore, its acceleration is
[tex]a=\frac{444 m/s-0 m/s}{1.83 s}=242.6 m/s^2[/tex]
2. Distance travelled by the sled: 406.3 m
Explanation:
We can solve this part of the problem by using the following SUVAT equation:
[tex]v^2 - u^2 = 2ad[/tex]
where d is the distance travelled by the sled.
By using v = 444 m/s, u = 0 m/s, and a = 242.6 m/s^2, we can re-arrange the equation and find d:
[tex]d=\frac{v^2-u^2}{2a}=\frac{(444 m/s)^2-(0 m/s)^2}{2(242.6 m/s^2)}=406.3 m[/tex]
