Answer:
C.4.18g
The amount will remain after 12 days is 4.18 g
Step-by-step explanation:
we can use formula
[tex]P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }[/tex]
where
h is half life time
t is time in days
Po is initial quantity
P(t) is the quantity after t days
we are given
Curium-243 has a half-life of 28.5 days
[tex]h=28.5[/tex]
In a sample of 5.6 grams of curium-243
so,
[tex]P_0=5.6[/tex]
now, we can plug values
[tex]P(t)=5.6(\frac{1}{2})^{\frac{t}{28.5} }[/tex]
now, we can plug t=12
[tex]P(12)=5.6(\frac{1}{2})^{\frac{12}{28.5} }[/tex]
[tex]P(12)=4.18253[/tex]
So,
The amount will remain after 12 days is 4.18 g
Answer:
The correct answer option is C. 4.18 g.
Step-by-step explanation:
We are given that Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243 and we are to find how many grams will remain after 12 days.
To find the number of remaining grams, we will use the following formula:
[tex]A(t)=A_0(\frac{1}{2}) ^{\frac{t}{h} }[/tex]
where t is the time and h is the half life.
So substituting in the given values to get:
[tex]A(t)=5.6(\frac{1}{2} )^{\frac{12}{28.5} }[/tex]
[tex]A(t)=5.6*0.747[/tex]
[tex]A(t)=4.18[/tex]
Therefore, 4.18 grams of curium-243 will remain after 12 days.
