Respuesta :
Since hemophilia is an X-linked recessive disorder, the probability depends on the X alleles.
So, if father has dominant allele (H), the probability that a female child would suffer from hemophilia (genotype: hh) is 0%, no matter of mother's genotype:
Father Mother
Parents: H x Hh
Daughter: HH or Hh
Father Mother
Parents: H x HH
Daughter: HH
Father Mother
Parents: H x hh
Daughter: Hh or Hh
But, if the father has recessive allele, the probability that a female child would suffer from hemophilia (genotype: hh) will depend on mother's genotype.
If mother is dominant homozygous, there will be 0% of possibility:
Father Mother
Parents: h x HH
Daughter: Hh
If mother is recessive homozygous, the possibility is 100%:
Father Mother
Parents: h x hh
Daughter: hh
If mother is heterozygous, the possibility is 50%:
Father Mother
Parents: h x Hh
Daughter: Hh or hh
So, if father has dominant allele (H), the probability that a female child would suffer from hemophilia (genotype: hh) is 0%, no matter of mother's genotype:
Father Mother
Parents: H x Hh
Daughter: HH or Hh
Father Mother
Parents: H x HH
Daughter: HH
Father Mother
Parents: H x hh
Daughter: Hh or Hh
But, if the father has recessive allele, the probability that a female child would suffer from hemophilia (genotype: hh) will depend on mother's genotype.
If mother is dominant homozygous, there will be 0% of possibility:
Father Mother
Parents: h x HH
Daughter: Hh
If mother is recessive homozygous, the possibility is 100%:
Father Mother
Parents: h x hh
Daughter: hh
If mother is heterozygous, the possibility is 50%:
Father Mother
Parents: h x Hh
Daughter: Hh or hh