Assuming that the given base is a weak monoprotic base, the pH of the solution can be calculated as follows:
Write the balanced reaction and ice chart:
BOH --> OH- + B+
i 0.32 0 0
c -x x x
e 0.32-x x x
Kb = x^2/ (0.32-x)
x = 1.21x10^-3 = [OH-]
pOH = -log[OH-] = -log[1.21x10^-3] = 2.917
pH = 14 - pOH = 14 - 2.917 = 11.08