Respuesta :
First write the inequality: 15[tex] \leq [/tex]4.75x +3.50
Then to solve, first subtract 3.50 from both sides to get:
11.50[tex] \leq [/tex]4.75x
Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.
Then to solve, first subtract 3.50 from both sides to get:
11.50[tex] \leq [/tex]4.75x
Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.
Answer: The required inequality is,
4.75 b +3.50 ≤ 15.00
Step-by-step explanation:
Here, b represents the number of bags of fruit bought by her,
Since, the cost of each bag of fruits = $ 4.75,
⇒ The cost of b bags of fruit = 4.75b dollars,
Also, she buy one box of crackers that costs $3.50,
Thus, her total expenditure = 4.75 b + 3.50
According to the question,
Her total expenditure can not exceed to $ 15.00,
⇒ 4.75 b + 3.50 ≤ 15.00
Which is the required inequality that is used to determine the maximum number of bags of fruit bought by her.