Answer:
probability that he scores a goal both times is [tex]13.7%[/tex].
Step-by-step explanation:
It is given that Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.
Therefore, P(X)=0.63.
Thus, the probability of getting success in his shoots will be,
[tex]P(X^{c})=1-P(X)=1-0.63=0.37[/tex]
probability that he scores a goal both times is =[tex]P(X^c){\times}P(X^c)[/tex]
=[tex]0.37{\times}0.37[/tex]
=[tex]0.137[/tex]
=13.7%
Answer:
13.69%
Step-by-step explanation:
Correct for edmentum/plato users
