WILL GIVE BRAINLIEST!
The atoms in an oxygen molecule complete one vibration in a time interval of 2.11×10−14s. Determine the frequency of vibration of O2.


Express your answer to three significant figures and include the appropriate units.

Respuesta :

4.74 × 10¹³ Hz.

Explanation

[tex]\text{Frequency} = \dfrac{1}{\text{Time Interval}}[/tex].

In other words,

[tex]f = \dfrac{1}{T}[/tex].

[tex]T = 2.11 \times 10^{-14}\; \text{s}[/tex]

[tex]f = \dfrac{1}{2.11 \times 10^{-14}\; \text{s}}\\\phantom{f} = 4.74 \times 10^{13} \; \text{s}^{-1}[/tex].

Note the unit. [tex]\text{s}^{-1}[/tex] or [tex]\dfrac{1}{s}[/tex] indicates 1 cycle per second. That is the same as 1 Hertz or [tex]\text{Hz}[/tex]. As a result,

[tex]f =4.74 \times 10^{13} \; \text{Hz}[/tex].