Respuesta :

Sarith

Volume = nRT/P

n = number of particles (moles)

R = universal gas constant (0.0821)

T = temperature (Kelvin)

P = pressure (atm)

(Assuming you have 1 mole of Helium in a chemical reaction) We would need to convert grams to moles: 12.0g He x 1 mol He/4 molar mass of He = 3 mol He

Convert Celsius to Kelvin: 100*C + 273.15 = 373.15 K

Now we can set up the equation for volume: (3mol)(0.0821)(373.15)/1.2atm = 76.6 L of Helium gas

Cricetus

The Volume of helium will be "7752.8 L".

Given values are:

  • P = 1.2 atm
  • n = 12.0 g
  • R = 8.314
  • T = 100°C

or,

          = 373 K

As we know,

→ [tex]PV = nRT[/tex]

or,

→    [tex]V = \frac{nRT}{P}[/tex]

By substituting the values, we get

→        [tex]= \frac{12\times 8.314\times 373}{1.2\times 4}[/tex]

→        [tex]= \frac{37213.47}{4.8}[/tex]

→        [tex]=7752.8 \ L[/tex]  

Learn more about Volume of helium here:

https://brainly.com/question/10096599

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