Answer: The new volume is 2.1 L.
Explanation:
Use the formula Boyle's law.
[tex]P_{1}V_{1}=P_{2}V_{2}[/tex]
Here, [tex]P_{1}, P_{2}[/tex] are the initial pressure and the final pressure and [tex]V_{1},V_{2}[/tex] are the initial and the final volumes.
As, it is given in the problem, a helium balloon has a volume of 2.00 L at 101 kPa. As the balloon rises, the pressure drops to 97.0 kPa.
[tex]P_{1}V_{1}=P_{2}V_{2}[/tex]
Put P_{1}=101 kPa,V_{1}=2.00L and P_{2}=97.0 kPa.
[tex](101 )(2.00)=(97.0)V_{2}[/tex]
[tex]V_{2}=\frac{(101)(2.00)}{97}\\V_{2}=2.1 L[/tex]
Therefore, the new volume is 2.1 L.
