A balloon rises vertically at the rate of 10 feet per second. It encounters a wind that gives a horizontal displacement of 5 feet per second. Find the angle its path makes with the horizontal.

Respuesta :

Answer:

63.44°

Step-by-step explanation:

We are given from the figure,

Vertical distance = 10 feet

Horizontal distance = 5 feet.

Trigonometric rule for the right triangles gives us,

[tex]\tan x=\frac{perpendicular}{base}[/tex]

i.e. [tex]\tan x=\frac{10}{5}[/tex]

i.e. [tex]\tan x=2[/tex]

i.e. [tex]x=\arctan 2[/tex]

i.e. x= 63.44°

Hence, the angle made by the path with the horizontal is 63.44°

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