Respuesta :
Answer:
Inequality is [tex]8x+45 < 12x+5[/tex] and value of x>10.
Step-by-step explanation:
Given : Adam is ordering pizza for a company party that he needs to have catered.
Company A charges $8 for each pizza and a delivery/set-up fee of $45. Company B charges $12 for each pizza and a delivery/set-up fee of $5.
To find : Which inequality can be used to find x, the least number of pizzas that can be ordered so that the total charge for Company A is less than the total charge for Company B?
Solution : Let x be the number of pizza
Company A charges $8 for each pizza and a delivery/set-up fee of $45.
Total charge of Company A is [tex]8x+45[/tex]
Company B charges $12 for each pizza and a delivery/set-up fee of $5.
Total charge of Company B is [tex]12x+5[/tex]
The total charge for Company A is less than the total charge for Company B
i.e, Inequality form [tex]8x+45 < 12x+5[/tex]
[tex]\Rightarrow 45-5< 12x-8x[/tex]
[tex]\Rightarrow 40< 4x[/tex]
[tex]\Rightarrow \frac{40}{4}< x[/tex]
[tex]\Rightarrow 10< x[/tex]
or x> 10
Therefore, Inequality is [tex]8x+45 < 12x+5[/tex] and value of x>10.
