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After pulling his car off to the side of the road during a rainstorm, travis isdismayed to find that the car has become stuck in the mud. travis ties oneend of a rope to the front of the car and the other end to a tree 12.00 m awayas shown.


a.if travis can exert a force of 610 n on the rope, moving it 1.00 min the direction shown, how much force will the rope exert on the car?


b.whyis this method better than simply tying a rope to the front of the car andpulling the car straight out?

Respuesta :

Part a)

here as per the situation shown we can say that the tension force at the position of applied force is given as

[tex]F = 2Tsin\theta[/tex]

here

[tex]\theta[/tex] = angle of rope with horizontal

[tex]tan\theta = \frac{1}{6}[/tex]

so we will have

[tex]\theta = 9.46 degree[/tex]

now we can say

[tex]F = 610 N[/tex]

[tex]610 = 2Tsin9.46[/tex]

[tex]T = 1855.2 N[/tex]

so the tension force in the string is 1855.2 N

Part B)

this method is better then pulling the car directly because if we pull the car directly then the force on the car is 610 N while in this case we get almost 3 times more force so it is better way to pull the car

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