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The polynomial is a difference squares. Use the formula a^2 -b^2=(a+b)(a-b) to factor completely. 81x^2-49 the value of a is the value of b is the product of the prime factors is

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carlosego

Answer: [tex](9x)^{2}-(7)^{2}=(9x-7)(9x+7)[/tex]

Step-by-step explanation:

1. By definition you have that the difference of squares is:

[tex]a^{2}-b^{2}=(a+b)(a-b)[/tex]

2. Given the polynomial:

[tex]81x^{2}-49[/tex]

You can identify that there are two terms whose signs are different and they are perfect squares.

3. Therefore, you have:

 [tex]81x^{2}-49=(9x)^{2}-(7)^{2}=(9x-7)(9x+7)[/tex]

zainebamir540

Answer:

(9x+7)(9x-7)

Step-by-step explanation:

We have given an expression.

81x²-49

We have to use difference formula which is given in question.

a²-b² =(a+b)(a-b)

We have to write given expression in above formula.

81x²-49 = (9x)²-(7)²

Using given formula , we have

81x²-49 = (9x+7)(9x-7)

Hence, the factors of given expression are (9x-7) and (9x+7).

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