Respuesta :
Answer: 1951.6 g
Explanation:
Molarity : It is defined as the number of moles of solute present in one liter of solution.
Moles of HCl=[tex]Molarity\times {\text { Volume in L}[/tex]
Moles of HCl=[tex]3.5M\times 8.2L=28.7moles[/tex]
[tex]Zn(s)+2HCl (aq)\rightarrow ZnCl_2(aq)+H_2(g)[/tex]
From the given balanced chemical equation,
2 moles of hydrogen chloride react with 1 mole of Zinc.
28.7 moles hydrogen chloride react with=[tex]\frac{1}{2}\times 28.7=14.35[/tex] moles of Zinc.
Mass of [tex]ZnCl_2=Moles\times {\text{Molar mass}}[/tex]
Mass of [tex]ZnCl_2=14.35\times 136g/mol=1951.6g[/tex]
Thus 1951.6 g of zinc metal will react completely with 8.2 liters of 3.5 M HCl.
Answer: 938.203 grams of zinc metal will react completely with 8.2 liters of 3.5 M HCl.
Explanation:
Molarity of the HCl solution = 3.5 M = 3.5 mol/L
Volume of the HCl solution = 8.2 l
[tex]Molarity=3.5 mol/L=\frac{\text{Moles of HCl}}{\text{Volume in liters}}[/tex]
Moles of HCl = [tex]3.5 mol/L\times 8.2 L=28.7 moles[/tex]
[tex]Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)[/tex]
According to reaction 2 moles of the HCl reacts with 1 mole of Zn metal.
Then 28.7 moles of HCl will react with:
[tex]\frac{1}{2}\times 28.7[/tex] moles of Zinc metal that is 14.35 moles.
Mass of the zinc metal required to completely react with given HCl solution is:
Mass of Zinc = Moles of zinc × Atomic Mass of zinc
= 14.35 mol × 65.38 g/mol = 938.203 g
938.203 grams of zinc metal will react completely with 8.2 liters of 3.5 M HCl.
