The volume of a right triangular prism is 72 cubic feet. The height of the prism is 9 feet. The triangular base is an isosceles right triangle.What is the area of the triangular base?

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Answer:

The area of the triangular base = 8 ft²

Step-by-step explanation:

The formula of a volume of a prism:

[tex]V=A_BH[/tex]

[tex]A_B-area\ of\ a\ base\\H-height[/tex]

We have

[tex]V=72\ ft^3,\ H=9\ ft[/tex]

Substitute:

[tex]72=9A_B[/tex]             divide both sides by 9

[tex]8=A_B\to A_B=8\ ft^2[/tex]

The area of the triangular base of the given prism with a volume of 72 cubic feet and a height of 9 feet is 8 sq. feet. It is calculated by using the volume of a prism formula.

The volume of the prism:

The volume of the prism with a base area and height is given as

Volume = Area of the base of the prism × height of the prism

i.e.,  V = [tex]B_a[/tex] × h

Here the base of the prism is an isosceles right triangle. So, the volume is given by

V = Area of isosceles right triangle × height of the prism

Calculating the area of the triangular base of the prism:

Given that volume of the prism is 72 cubic feet and the height of the prism is 9 feet.

Thus, the area of the triangular base is calculated as follows:

V = Area of triangular base × height of the prism

Area of the triangular base = Volume/height of the prism

⇒ Area of the triangular base =  [tex]\frac{72}{9}[/tex]

∴  Area of the triangular base = 8 sq. feet

Therefore, the area of the triangular base for the given right triangular prism is 8 sq. feet

Learn more about the volume of a prism here:

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