[15 Points, Heeeeelp]
Complete the half equations by balancing it and identify as either oxidation or reduction.

Cl^- (aq) → Cl2 (g)

F^- (aq) → F2 (g)

S (s) → S^2- (aq)

H2 (g) → H^+ (aq)

O2 (g) → O^2 (aq) ​

Respuesta :

Answer: The half reactions are given below.

Explanation:

Oxidation reactions are defined as the reactions in which a chemical species looses its electrons. The oxidation state of the specie increases.

[tex]X\rightarrow X^{n+}+ne^-[/tex]

Reduction reactions are defined as the reactions in which a chemical species gains its electrons. The oxidation state of the specie gets reduced.

[tex]X+ne^-\rightarrow X^{n-}[/tex]

For the given reactions:

1.) [tex]Cl^-(aq)\rightarrow Cl_2(g)[/tex]

Here, the oxidation state is getting increased, therefore it is an oxidation reaction. The equation for this follows:

[tex]2Cl^-(aq.)\rightarrow Cl_2(g)+2e^-[/tex]

2.) [tex]F^-(aq.)\rightarrow F_2(g)[/tex]

Here, the oxidation state is getting increased, therefore it is an oxidation reaction. The equation for this follows:

[tex]2F^-(aq.)\rightarrow F_2(g)+2e^-[/tex]

3.) [tex]S(s)\rightarrow S^{2-}(aq)[/tex]

Here, the oxidation state is getting reduced, therefore it is an reduction reaction. The equation for this follows:

[tex]S(s)+2e^-\rightarrow S^{2-}(aq)[/tex]

4.) [tex]H_2(g)\rightarrow H^+(aq.)[/tex]

Here, the oxidation state is getting increased, therefore it is an oxidation reaction. The equation for this follows:

[tex]H_2(g)\rightarrow 2H^+(aq.)+2e^-[/tex]

5.) [tex]O_2(g)\rightarrow O^{2-}(aq.)[/tex]

Here, the oxidation state is getting reduced, therefore it is an reduction reaction. The equation for this follows:

[tex]O_2(g)+4e^-\rightarrow 2O^{2-}(aq.)[/tex]