Answer: Amount of sodium chloride produced is 25.43 grams.
Explanation:
To calculate the moles:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}[/tex]
Given: Mass of sodium = 10 g
Molar mass of sodium = 23g/mol
[tex]\text{Moles of sodium}=\frac{10g}{23g/mol}=0.4347mol[/tex]
The balanced equation is:
[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]
By Stoichiometry of the reaction,
2 moles of sodium produces 2 moles of sodium chloride
So, 0.4347 moles of sodium will produce =[tex]\frac{2}{2}\times 0.4347=0.4347mol[/tex] of sodium chloride.
Molar mass of sodium chloride = 58.5 g/mol
Putting values in equation 1, we get:
[tex]0.4347mol=\frac{\text{Mass of NaCl}}{58.5g/mol}=25.43g[/tex]
Hence, amount of sodium chloride produced is 25.43 grams.
