Answer:
Value of [tex]x = \frac{19}{2}[/tex]
Step-by-step explanation:
Given: Two triangles ΔABC and ΔAED are congruent.
Sides AE= 3 EC= 5 and AD = (x-2), BD = (x+3)
To find: the value of x.
Solution: Since given two triangles ΔABC and ΔAED are congruent.
Therefore sides [tex]\frac{3}{8} = \frac{(x-2)}{(x-2)+(x+3)} = \frac{x-2}{2x+1}[/tex]
By cross multiplication 8(x-2) = 3(2x+1)
8x - 16 = 6x + 3
8x -6x = 16 + 3
2x = 19
x = [tex]\frac{19}{2}[/tex]
So the value of x = 19/2.
