Answer:
see explanation
Step-by-step explanation:
Assuming the fractions are being multiplied
Factorise the denominators of both fractions
x² - 3x - 10 = (x - 5)(x + 2)
x² + x - 12 = (x + 4)(x - 3)
The product can now be expressed as
[tex]\frac{x-5}{(x-5)(x+2)}[/tex] × [tex]\frac{x+2}{(x+4)(x-3)}[/tex]
Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving
[tex]\frac{1}{(x+4)(x-3)}[/tex] = [tex]\frac{1}{x^2+x-12}[/tex]
