For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
[tex]y = mx + b[/tex]
Where:
m: It's the slope
b: It is the cutoff point with the y axis
We find the slope with the given points:
[tex]m = \frac {y2-y1} {x2-x1} = \frac {401-450} {14-7} = \frac {-49} {7} = - 7[/tex]
Thus, the line is given by:
[tex]y = -7x + b[/tex]
We substitute a point to find "b":
[tex]450 = -7 (7) + b\\450 = -49 + b\\450 + 49 = b\\b = 499[/tex]
Finally, the equation is:
[tex]y = -7x + 499[/tex]
Answer:
[tex]y = -7x + 499[/tex]
