Answer: 2.4 ml
Solution :
Molar mass of [tex]NH_3[/tex] = 17 g/mole
Given,: 28% w/w of [tex]NH_3[/tex] solution means 28 g of ammonia in 100 g of solution.
Mass of solution = 100 g
Now we have to calculate the volume of solution.
[tex]Volume=\frac{Mass}{Density}=\frac{100g}{0.899g/ml}=111.2ml[/tex]
Molarity : It is defined as the number of moles of solute present in one liter of solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n = moles of solute [tex]NH_3=\frac{\text {given mass}}{\text {molar mass}}=\frac{28}{17}=1.65moles[/tex]
[tex]V_s[/tex] = volume of solution in liter = 0.11 L
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{1.65moles}{0.11L}=15mole/L[/tex]
Using molarity equation:
[tex]M_1V_1=M_2V_2[/tex]
[tex]15\times V_1=0.036\times 1.0\times 10^{3}[/tex]
[tex]V_1=2.4ml[/tex]
