find x if CE = x+12 and IE = 2x-6
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Answer:
x = 8
Step-by-step explanation:
Givens
By inference (see the last comment about the question, I is the end point of a side bisector. (The asker has said that all other questions have to do with side bisectors).
So CI and IE are equal. That means that CE = two times the size of CI
CE = x + 12
IE = 2x - 6
CE = 2* IE (property of a bisector.
Solution
CE = 2*IE
x + 12 = 2*(2x - 6) Remove the brackets.
x + 12 = 4x - 12 Add 12 to both sides
x + 12 +12 = 4x-12+12 Combine
x + 24 = 4x Subtract x from both sides
x - x + 24 = 4x - x Combine
24 = 3x Divide by 3
24/3 = 3x/3
x = 8