In this problem, we have an initial velocity [tex]v_{i}=3m/s[/tex] jump upwards (opposite direction to gravity) with the acceleration due to gravity [tex]g=-9.8m/s^2[/tex] , finally the player will reach to final velocity in the air [tex]v_{f}[/tex]
Using the equation of motion, the third equation states that:
[tex]v_{f}^{2} =v_{i} ^{2}+2gh[/tex]
where h is the height , the distance which the player reach in air
Thus
[tex]0^{2} =3 ^{2}+2*(-9.8)*h[/tex]
[tex]h=\frac{3^2}{2*9.8}= \frac{9}{19.6}= 0.459m[/tex]
