Answer:
The value which completes the table is:
3
Step-by-step explanation:
We are given a odd-degree( degree-5) function f(x) by:
[tex]f(x)=x^5+(x+3)^2[/tex]
Now, we are asked to complete the table.
i.e. we are asked to find the value of the function f(x) when x= -1
So, when x= -1 we have:
[tex]f(-1)=(-1)^5+(-1+3)^2\\\\\\f(-1)=-1+(2)^2\\\\\\i.e.\\\\\\f(-1)=-1+4\\\\\\i.e.\\\\\\f(-1)=3[/tex]
Hence, the complete table is given by:
x f(x)
-2 -31
-1 3
0 9
1 17
The answer is: 3
