If 17.5 moles of ethanol were produced, how many moles of glucose were there in the beginning?

The reaction is (Ignoring the state symbols)
[tex]C_6H_{12}O_6 \rightarrow 2C_2H_5OH + 2CO_2[/tex]
This equation tells us that for every 2 molecules of ethanol, there is one mole of glucose.
So there is 17.5 / 2 moles of glucose in the beginning, which is 8.75 moles.
Based on the mole ratio of the reaction, 8.75 moles of glucose were present at the beginning.
The mole ratio of a reaction gives the ratio in which moles of reactants combine to form moles of products.
The mole ratio of a reaction is determined from a balanced equation of the reaction.
The equation of the reaction of the conversion of glucose to ethanol us given below:
C6H12O6 ---> 2C2H5OH + 2CO2
From the mole ratio of reactants and products;
Therefore 17.5 moles of ethanol will be produced by 15.5/2 = 8.75 moles of glucose.
Learn more about mole ratio at: https://brainly.com/question/12099869