Answer: Prop-1-ene will be obtained as a product.
Explanation:
Alcohols on heating with sulfuric acid results in elimination of the water molecule to form an alkene.
When the propanol is heated in presence of [tex]H^+[/tex] and sulphuric acid will give prop-1-ene as a product.
[tex]CH_3CH_2CH_2OH\overset{H^+/H_2SO_4}\rightarrow CH_3CH=CH_2+H_2O[/tex]