Answer:
[tex]y=-\frac{5}{3}x-2[/tex]
Step-by-step explanation:
The first line has a slope of -5/3 found using the points in the slope formula.
[tex]m=\frac{y_2-y_1}{x_2-x_1} =\frac{-9--4}{0--3}=\frac{-9+4}{0+3}=\frac{-5}{3}[/tex]
Parallel lines have the same slope. So -5/3 is the slope of the second line. Write its equation using the point slope form [tex]y-y_1=m(x-x_1)[/tex].
[tex]y--7=-\frac{5}{3}(x-3)\\y+7 = -\frac{5}{3}(x-3)\\y=-\frac{5}{3}x + 5 -7\\y=-\frac{5}{3}x-2[/tex]
