contestada

What is the ratio ef/ei of the final electric field strength ef to the initial electric field strength ei if q is doubled?

Respuesta :

As we know that electric field at a point due to a point charge is given by

[tex]E = \frac{kq}{r^2}[/tex]

here we can see that electric field is directly depends on the magnitude of charge

so if we change the magnitude of charge by some factor then electric field will change by same factor

so here as given that charge is doubled

then electric field due to that charge at the same point also get doubled

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