Find the slope of the tangent to the graph of the given function at the indicated point. HINT [Recall that the slope of the tangent to the graph of f at x = a is f '(a).] f(x) = x 8 − 1; (−8, −2)

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5naka

f'(x)

[tex] = 8{x}^{7} [/tex]

slope

[tex]8 {( - 8)}^{7} = - {8}^{8} [/tex]