Respuesta :
Answer: The work done is 245000 J.
Explanation:
The formula for the force due to the weight of the object is as follows;
[tex]F=mg[/tex]
Here, m is the mass of the object and g is the acceleration due to gravity.
Put m=500 kg and g=9.8 meter per second.
[tex]F=(500)(9.8)[/tex]
[tex]F=4900 N[/tex]
The formula for the work done is as follows;
[tex]W=Fs[/tex]
Here, F is the force and s is the displacement.
Put F=4900 N and s=50.0 m.
[tex]W=(4900)(50)[/tex]
[tex]W=245000 J[/tex]
Therefore, the work done is 245000 J.
Answer : Work done, W = 245,000 J
Explanation :
It is given that,
Mass of the system, m = 500 kg
Distance, d = 50 m
According to the definition of work done, [tex]W=force\times displacement[/tex]
So, work done to lift the system of electric motor and a pulley is :
[tex]W=mg\times h[/tex]
[tex]W=500\ kg\times 9.8\ m/s^2\times 50\ m[/tex]
[tex]W=245,000\ J[/tex]
Hence, this is the required solution.
