Which statement about sqrt x- sqrt (x-5) =1 is true? x = 4 is a true solution. x = 4 is an extraneous solution. x = 9 is a true solution. x = 9 is an extraneous solution.

Respuesta :

Answer: (C) x = 9 is a true solution.

Step-by-step explanation: Edge 2021

x = 9 is a true solution to the equation [tex]\sqrt{x} -\sqrt{x-5} =1[/tex]

True solutions of equations

The given equation is:

[tex]\sqrt{x} -\sqrt{x-5} =1[/tex]

Rearrange the equation

[tex]\sqrt{x-5} = \sqrt{x} -1[/tex]

Square both sides

[tex]\sqrt{x-5}^2=(\sqrt{x} -1)^2 \\\\x-5=x-2\sqrt{x} +1\\\\2\sqrt{x} =1+5\\\\2\sqrt{x} =6[/tex]

Divide both sides by 2

[tex]\frac{2\sqrt{x} }{2}= \frac{6}{2} \\\\\sqrt{x} =3[/tex]

Square both sides

[tex]\sqrt{x} ^2=3^2\\\\x=9[/tex]

Therefore, the solution to the equation [tex]\sqrt{x} -\sqrt{x-5} =1[/tex] is x = 9

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