Answer:
16.7 mF
Explanation:
The total capacitance of two capacitors connected in series is given by the formula:
[tex]\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}[/tex]
in our problem, we have:
C1 = 45 mF is the capacitance of the first capacitor
C2 = 26 mF is the capacitance of the second capacitor
Substituting into the equation, we find:
[tex]\frac{1}{C}=\frac{1}{45 mF}+\frac{1}{26 mF}=0.06 mF^{-1}\\C=\frac{1}{0.06 mF^{-1}}=16.7 mF[/tex]
