Answer:
521.8 V
Explanation:
The RMS value of the voltage of an AC signal is given by
[tex]V_{rms}=\frac{V_0}{\sqrt{2}}[/tex]
where
[tex]V_0[/tex] is the peak voltage, which corresponds to the amplitude of the AC waveform
In this problem, we know the RMS voltage
[tex]V_{rms}=369 V[/tex]
Therefore, we can re-arrange the previous equation to find the peak voltage (the amplitude of the waveform):
[tex]V_0 = \sqrt{2}V_{rms}=\sqrt{2}(369 V)=521.8 V[/tex]
