Answer:
The graph in the attached figure
Step-by-step explanation:
we have
[tex]h=-16t^{2}+104t+56[/tex]
Using a graphing tool
see the attached figure
This is the equation of a vertical parabola open downward
The vertex is the point (3.25,225) (a maximum)
The zero's of the function or the t-intercepts are the points (-0.5,0) and (7,0)
The h-intercept of the function is the point (0,56)
The domain of the function are all real numbers
The range of the function [tex]h\leq225[/tex] ----> All real numbers less than or equal to 225
