A chemist adds 0.80 L of a 3.2 x 10^-5 mmol/L silver(II) oxide (AgO) solution to a reaction flask. Calculate the micromoles of silver(II) oxide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

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Answer:

1 mmol = 1,000 um

[tex]0.80l*\frac{3.2*10^{-5} mmol}{1l}*\frac{1,000um}{1mmol} = 2.6 * 10^{-2}  \ um[/tex]

25.6 micromoles when a chemist adds 0.80 L of a 3.2 x [tex]10^{-5}[/tex] mmol/L silver(II) oxide (AgO) solution to a reaction flask.

What are moles?

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]

of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

The mass of silver nitrate is 0.438 kg

Explanation:

Step 1: Data given

Volume =0.80 L

Molarity silver nitrate (AgO) = 3.2 x [tex]10^{-5}[/tex]M

Molar mass of AgO = 123.868 g/mol

Step 2: Calculate moles AgO

Number of moles = molarity x volume

Number of moles = 3.2 x [tex]10^{-5}[/tex]M x 0.80 L

Number of moles  AgO = 2.56×[tex]10^{-5}[/tex] moles

Multiply the number of moles by 1,000,000 to calculate micromoles.

2.56×[tex]10^{-5}[/tex] moles x 1,000,000

25.6 micromoles

Hence, 25.6 micromoles when a chemist adds 0.80 L of a 3.2 x [tex]10^{-5}[/tex] mmol/L silver(II) oxide (AgO) solution to a reaction flask.

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