1st - True.
Reason: The remaining shaded portion is [tex]\frac{9}{10}[/tex] and she will use [tex]\frac{3}{5}[/tex] of it, so remaining will be =
[tex]\frac{9}{10}-\frac{3}{5}=\frac{3}{10}[/tex] parts
2nd - True.
The given fractions [tex]\frac{3}{5}[/tex] and [tex]\frac{6}{10}[/tex] are equal.
3rd - False
As calculated above in the 1st part, 3/10 parts will be left, so this question is false.
Answer:
Step-by-step explanation:
The image shows that she has 9/10 meters of the string available.
She wants to use 3/5 meters, so the part remaining is
[tex]\frac{9}{10}-\frac{3}{5}=\frac{45-30}{50}=\frac{15}{50}=\frac{3}{10}[/tex]
Basically, the statement 7a is true, because with that difference we can find the string remaining. Also, with this results, we can say that 7c is false, becasue 1/5 meters is not the string remaining, it's 3/10.
Additionally, 7b is true, because 3/5 and 6/10 are actually equivalent factors, observe that if you multiply the first fraction by two, you'll get the second fraction.
