Helpppp!

Mark sold 461 tickets for the school play.

Student tickets cost $3 and adult tickets cost $4. Mark's sales totaled $1624.

Write and solve a system of equations to determine how many adult and student tickets Mark sold?


a. 220 adult, 241 student

b. 236 adult, 225 student

c. 241 adult, 220 student

d. 225 adult, 236 student

Respuesta :

Answer:

Step-by-step explanation:

3s+4a=1624

S+a=461

3s+3a=1383

(3s+4a=1624)

-(3s+3a=1383)

0+a=241

A=241

241 adult tickets were sold

S+a=461

S+241=461

S=220

220 student tickets were sold

You can check by doing: (220×3)+(241×4)=1624

S=student tickets

A=adult tickets

The number of students will be 220 and the number of adults will be 241.

What is the linear system?

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Mark sold 461 tickets for the school play.

Student tickets cost $3 and adult tickets cost $4. Mark's sales totaled $1624.

Let x be the number of students and y be the number of adults. Then we have equations

   x + y = 461     ...1

3x + 4y = 1624  ...2

By solving the equations 1 and 2, then we have

x = 220 and y = 241

Thus, the correct option is C.

More about the linear system link is given below.

https://brainly.com/question/20379472

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