Answer:
The freezing point of the solution is - 3.90 °C.
Explanation:
- We can solve this problem using the relation:
ΔTf = (Kf)(m),
where, ΔTf is the depression in the freezing point.
Kf is the molal freezing point depression constant of water = - 1.86 °C/m,
m is the molality of the solution (m = 2.1 m).
∴ ΔTf = (Kf)(m) = (-1.86 °C/m)(2.1 m) = - 3.90 °C.
∵ The freezing point if water is 0.0 °C and it is depressed by - 3.90 °C.
∴ The freezing point of the solution is - 3.90 °C.
