For this case, we must find the area of the polygon shown in the figure. To do this, we divide the figure into two parts.
[tex]A_ {1} = l_ {1} * w_ {1}\\A_ {1} = 24 * 11\\A_ {1} = 264 \ square \ units[/tex]
On the other hand:
[tex]A_{2} = l_ {2} * w_ {2}\\A_{2} = (4 + 4 + 11) * 4\\A_{2} = 19 * 4\\A_ {2} = 76 \ square \ units[/tex]
So, the total area is:
[tex]A_ {t} = A_ {1} + A_ {2}\\A_ {t} = 264 \ square \ units + 76 \ square \ units\\A_ {t} = 340 \ square \ units[/tex]
Answer:
[tex]340 \ square \ units[/tex]
