Answer:
Option D. [tex]392.5\ units^{3}[/tex]
Step-by-step explanation:
we know that
The volume of the cone is equal to
[tex]V=\frac{1}{3} \pi r^{2}h[/tex]
In this problem we have
[tex]h=15\ units[/tex]
[tex]r=5\ units[/tex]
substitute the values
[tex]V=\frac{1}{3} (3.14)(5^{2})(15)=392.5\ units^{3}[/tex]