The length of a new rectangular playing field is 8 yards longer than double the width. If the perimeter of the rectangular playing field is 280 yards, what are its dimensions.

Respuesta :

Let

width,w

length, l = 2w +8...eqn 1

perimeter, p = 2 (l + w)...eqn 2

subst for l in eqn 2...

p = 2(2w +8 + w) = 2 (3w + 8) = 280

280 = 6w + 16

w = 264 /6 = 44

subst for w in eqn 1

l = 2× 44 + 8 = 96

length = 96yds

width = 44 yds

The dimensions are given below.

  • length = 96 yards.
  • width = 44 yards.

Let the width be w.

Length, l = 2w +8.   (I)

Perimeter, p = 2 (l + w).   (II)

Substituting for (l) in equation (II)

p = 2(2w +8 + w)

p = 2 (3w + 8)

p = 280

280 = 6w + 16

w = 264 /6

w = 44

Substituting the value of width in equation (I)

l = 2× 44 + 8

l = 96

length = 96 yards

width = 44 yards

What does dimension mean?

Dimensions in mathematics are the measure of the scale or distance of an item or place or space in one path. In easier terms, it's far the size of the duration, width, and peak of something.

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