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Which is a correct statement about the description “two less than the quotient of a number cubed and sixteen, increased by eight” when n = 4?

The correct expression is . n cubed/16-2+8
The correct expression is . 2-n cubed/16+8
One of the steps to determining the value when n = 4 is 1-2+8.
One of the steps to determining the value when n = 4 is 2-1+8.
The value when n = 4 is 6.
The value when n = 4 is 7.
The value when n = 4 is 9.
The value when n = 4 is 10.

Respuesta :

calculista

Answer:

The correct expression is [tex]\frac{n^{3}}{16}-2+8[/tex]

The value when [tex]n=4[/tex] is [tex]10[/tex]

Step-by-step explanation:

Let

x------> a number

we know that

The algebraic expression of “two less than the quotient of a number cubed and sixteen, increased by eight” is equal to

[tex]\frac{n^{3}}{16}-2+8[/tex]

For [tex]n=4[/tex]

Substitute the value of n in the expression

[tex]\frac{4^{3}}{16}-2+8[/tex]

[tex]4-2+8[/tex]

[tex]10[/tex]

so

The value when [tex]n=4[/tex] is [tex]10[/tex]

You can symbolize the given values and can convert description to mathematical expression for given description here.

The correct statement for given description is  [tex]\dfrac{n^3}{16} - 2 + 8[/tex]

Given that:

  • The description about statement is:
  • "Two less than the quotient of a number cubed and sixteen, increased by eight"
  • and n = 4

How to go from description to forming symbolic representation?

"Two less than x" describes "x- 2"

"Quotient of x and y" describes  [tex]\dfrac{x}{y}[/tex]

"x increased by y" describes  [tex]x + y[/tex]

Thus, combining all three statements for given values:

[tex]\dfrac{n^3}{16}[/tex]  is the quotient and 2 is subtracted and 8 is increased which means 8 is added.

Thus, the resultant expression is:  [tex]\dfrac{n^3}{16} - 2 + 8[/tex]

How to evaluate the obtained expression at n=4?

Replace n with 4 and evaluate the expression as follows.

[tex]\dfrac{n^3}{16} - 2 + 8 |_{n=4} = \dfrac{4^3}{16} + 6 = 4 + 6 = 10[/tex]

Learn more about linear equations here:

https://brainly.com/question/14362668

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