Respuesta :

carlosego

Answer:

Center: (-3,-2)

Radius: √6

The graph is attached.

Step-by-step explanation:

The equation of the circle has the form:

[tex](x -h)^{2}+(y-k)^{2}=r^{2}[/tex]

Where (h,k) is the  point of the center of the circle and r is the radius of the circle.

The equation given in the problem is

[tex](x +3)^{2}+(y+2)^{2}=6[/tex]

 Therefore:

h=-3

k=-2

The center is at (-3,-2)

And the radius is:

[tex]r^2=6\\r=\sqrt{6}[/tex]

Then, you can graph it has you can see in the image attached.

Ver imagen carlosego
zainebamir540

Answer:

The center of circle is (-3,-2) and radius of circle is √6.

Step-by-step explanation:

We have given an equation of circle.

(x+3)²+(y+2) = 6

We have to plot the graph of circle.

(x-h)²+(y-k)² = r² where (h,k) is center and r is radius of circle.

Given equation is (x-(-3))²+(y-(-2))² = (√6)²

comparing above equation with standard equation, we have

(h,k) = (-3,-2) and r = √6

Hence, the center of circle is (-3,-2) and radius of circle is √6.

Ver imagen zainebamir540

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