Respuesta :
Answer;
Final temperature of the granite ≈ 44.82 °C
Explanation;
Let T be the equilibrium temperature (in °C) to be found.
Moles of water;
(1.45 L H2O) x (1000 mL/L) x (1.00 g/mL) / (18.01 g H2O/mol)
= 80.512 mol H2O
Heat gained by water;
= (75.3 J/(mol ·°C)) x (80.512 mol) x (T - 25.0)°C
= (6062.465 T - 151561.6)
Heat lost by granite;
= (0.790 J/(g ·°C)) x (276 g) x (596 - T)°C
= (129951.84 - 218.04 T)
Set the two expressions for heat gained/lost equal to each other:
6062.465 T - 151561.6= 129951.84 - 218.04 T
6280.505 T = 281513.44
T = 44.8234
T ≈ 44.82 °C
The temperature of the granite in Celsius is 44.82 °C.
What is the specific heat?
Specific heat is the amount of heat required to raise the temperature by 1 degree C of one gram of substance.
First we calculate the moles of water as:
n = W/M, where
W = given mass of water which we calculate by multiply volume & density = (1.45 L) x (1000 mL/L) x (1.00 g/mL)
M = molar mass of water = 18.01 g/mol
Moles of water = 1.45L x 1000mL/L x 1g/mL / 18.01g/mol = 80.512 mol
Let, the required temperature for the given question is T.
Heat absorbed by water will be calculated as:
Q = mcΔT, where
m = mass of water (in moles calculated)
c = specific heat of water = 75.3 J/mol ·°C (given)
ΔT = change in temperature
On putting values in the above equation, we get
Q = 80.512 mol x 75.3 J/mol ·°C x (T - 25.0)°C
Q = 6062.465 T - 151561.6 ................... (i)
Now heat released by the granite is also calculated by using the formula:
Q = mcΔT, where
m = mass of granite = 276g (given)
c = specific heat of granite = 0.790 J/g ·°C (given)
On putting all values on the above equation, we get
Q = 0.790 J/g·°C x 276g x (596 - T)°C
Q = 129951.84 - 218.04 T ................... (ii)
From (i) & (ii), we get
6062.465 T - 151561.6 = 129951.84 - 218.04 T
T = 44.82 °C
Hence, 44.82 °C is the final temperature of granite.
To know more about specific heat, visit the below link:
https://brainly.com/question/13439286
