Write the equation of each circle given its center and a point P that it passes through

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kudzordzifrancis kudzordzifrancis · Answer 1 · 2019-03-12T08:05:23+01:00

ANSWER

[tex] {x}^{2} + {y}^{2} = 4[/tex]

EXPLANATION

The circle passes through P=(2,0) and centered at (0,0).

The radius of this circle is

[tex]r = \sqrt{ {(2 - 0)}^{2} + {(0 - 0)}^{2} } = 2[/tex]

The equation is given by:

[tex] {x}^{2} + {y}^{2} = {r}^{2} [/tex]

This implies that

[tex] {x}^{2} + {y}^{2} = {2}^{2} [/tex]

[tex] {x}^{2} + {y}^{2} = 4[/tex]

Answer Link

zainebamir540 zainebamir540 · Answer 2 · 2019-03-12T10:32:18+01:00

Answer:

x²+y² = 4 is the equation of given circle.

Step-by-step explanation:

We have given the center (0,0) and a point P (2,0) from which the circle is passes.

So, the radius of the circle is :

r= [tex]\sqrt{((2-0)^{2}+(0-0)^{2}[/tex]

r= 2

The equation of circle is :

(x - x₁)² +(y - y₁)² = r² where (x₁,y₁) is the center of circle.

Putting the value in above equation we get,

(x-0)²+(y-0)² = (2)²

x²+y² = 4 is the equation of given circle.