Can someone explain the changing of the signs on both side of the equation?
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The whole equation is multiply my -1.
-2x2 + 5x + 5 = 0
Now multiply it with -1.
-1 (-2x2 + 5x + 5 = 0) and you get:
2x2 - 5x - 5 = 0.
It doesn't matter the answer will be the same.
Using the sign convention rule the equation [tex]\rm -2x^2 +5x + 5= 0[/tex] after changing the sign is transformed as [tex]\rm 2x^2 -5x - 5= 0[/tex].
Sign convention means the rule that is used when the sign is to be changed. It is applicable only when the equation is considered.
Given
[tex]\rm -2x^2 +5x + 5= 0[/tex] is a quadratic equation.
Multiply both sides by (-1). Then we have
[tex]\rm -\ 2 \ x^2 \ + \ 5 \ x \ + \ 5= 0\\\\\rm -1(-2x^2 +5x + 5 )= -1 * 0[/tex]
On simplifying, we have
[tex]\rm (-1)*(-2x^2 )+ (-1)*5x + (-1)*5= (-1)*0[/tex]
We know the sign convention rule
[tex]\rm Negative *Negative =Positive \\\\Negative*Positive = Negative \\\\Negative*Positive =Negative \\\\Positive*Positive =Positive[/tex]
Then the equation will be
[tex]\rm 2x^2-5x -5= 0[/tex]
Thus, the equation [tex]\rm -2x^2 +5x + 5= 0[/tex] after changing the sign is transformed as [tex]\rm 2x^2 -5x - 5= 0[/tex].
More about the sign convention link is given below.
https://brainly.com/question/25934508