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If the solution process is exothermic, then an increase in temperature usually results in:


an increase in solubility

a decrease in solubility

no change in the solubility

a nonpolar solution precipitating most of its solute

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UgandanChungus

In exothermic reactions, increasing temperature decreases the solubility of the solute. ... This is because in general heat energy is released as gas dissolves in solution i.e. the process is exothermic. Increasing temperature (increased heat energy) results in increased kinetic energy.

Answer: a decrease in solubility

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.[tex]solid +solvent\rightleftharpoons Solution[/tex]   [tex]\Delta H=-ve[/tex]

If a reaction is exothermic reaction in which heat is released in the reaction.

If in the equilibrium system, temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in temperature occurs. As, the backward reaction is a endothermic reaction, backward reaction will decrease the temperature.

Hence, the equilibrium will shift in the backward direction and thus solubility will decrease.

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