Answer: [tex]x_1=1.71\\x_2=-3.21[/tex]
Step-by-step explanation:
The quadratic formula is:
[tex]x=\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}[/tex]
Make the equation equal to zero:
[tex]4x^{2}+6x-22=0[/tex]
Given the equation shown in the problem, you have that:
[tex]a=4\\b=6\\c=-22[/tex]
When you substitute the values, you obtain:
[tex]x=\frac{-6+/-\sqrt{6^{2}-4(4)(-22)}}{2(4)}[/tex]
[tex]x_1=1.71\\x_2=-3.21[/tex]
