Answer:
The first five terms of the given sequence
3, 6, 11, 18, 27
Step-by-step explanation:
It is given that,
an=n² +2
To find the first five terms
a₁ = 1² + 2 = 1 + 2 = 3
a₂ = 2² + 2 = 4 + 2 = 6
a₃ = 3² + 2 = 9 + 2 = 11
a₄ = 4² + 2 = 16 + 8 = 18
a₅ = 5² + 2 = 25 + 2 = 27
Therefore the first five terms of the given sequence
3, 6, 11, 18, 27
The first five terms of the sequence. an=n2 +2 are 3, 6, 11, 18 and 27.
The sequence is given as n² + 2.
= n² + 2 = 1² + 2 = 1 + 2 = 3
= n² + 2 = 2² + 2 = 4 + 2 = 6
= n² + 2 = 3² + 2 = 9 + 2 = 11
= n² + 2 = 4² + 2 = 16 + 2 = 18
= n² + 2 = 5² + 2 = 25 + 2 = 27
Therefore, the first five terms of the sequence. an=n2 +2 are 3, 6, 11, 18 and 27.
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